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Q.

A wire of length l has a resistance R. If half of the length is stretched to make the radius half of its original value, then the final resistance of the wire is

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a

3 R

b

5 R

c

172R

d

9 R

answer is C.

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Detailed Solution

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Radius of R/2 is made halved by stretching so resistance becomes 

R2×16   (Resistance∝1r4)

So final resistance =R2+8R=17R2

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