Q.

A wire of length l  and mass per unit length 6.0×103kg/m  is put under tension of 540N  two consecutive frequencies that it resonates at are  420Hz and 490Hz , then l  in meters is _____

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answer is 2.142.

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Detailed Solution

nv2l=420      i n+1v2l=490     (ii) Divide i/ii            n=6 Substitute in equation (i) we have  6×v2l=420            Also,  v=Tμ=5406×103 6×5406×1032l=420 l=300140=2.142

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A wire of length l  and mass per unit length 6.0×10−3 kg/m  is put under tension of 540N  two consecutive frequencies that it resonates at are  420 Hz and 490 Hz , then l  in meters is _____