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A wire of resistance $10 Ω$ is bent to form a circle. P and Q are points on the circumference of the circle dividing it into a quadrant and are connected to a battery of 3 V and internal resistance $1 Ω$ as shown in the figure. The currents in the two parts of the circle are

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An Intiative by Sri Chaitanya

$\frac{6}{23} A and \frac{18}{23} A$

$\frac{3}{25} A and \frac{9}{25} A$

$\frac{5}{26} A and \frac{15}{26} A$

$\frac{4}{25} A and \frac{12}{25} A$

answer is A.

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