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Q.

A wire whose linear density is 5×10−3kg/m stretched between two points with a tension 450N. The wire resonates at a frequency of 420Hz. The next higher frequency at which the same wire resonates is 490Hz the length of the wire is ….m(round off to 1 decimal place)

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answer is 2.1.

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Detailed Solution

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From the given data

fundamental frequency = 490Hz - 420Hz = 70Hz

Fundamental frequency in a string is 

f=12l Tμ

⇒70=12l4505×10-3

⇒l=300140=2.1

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