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Q.

A woman walks on a straight road from her home to the market covering a distance of 3km at a speed of 5kmph. On finding the market closed, she instantaneously turns and walks back to home with a speed of 6kmph. The magnitude of her average velocity is

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a

5.45kmph

b

5.5kmph

c

Zero

d

2.73kmph

answer is A.

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Detailed Solution

Given that a woman walked from home to market with speed = 5kmph

Question Image

Returned from market to house with speed = 6mph

VAvg=st

Displacement is zero

VAvg=0t

∴VAvg=0

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