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Q.

A wooden block of mass 10 Kg is kept on the top of a table. The dimensions of the block are 40 cm × 20 cm × 10 cm. The pressure exerted by the wooden block from the side of 20 cm × 40 cm is


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a

4900 N/m2

b

5800 N/m2

c

1220 N/m2

d

1350 N/m2 

answer is C.

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Detailed Solution

A wooden block of mass 10 Kg is kept on the top of a table. The dimensions of the block are 40 cm × 20 cm × 10 cm. The pressure exerted by the wooden block from the side of 20 cm × 40 cm is 1220 N/m2.
Given that,
Mass of block (m) = 10 kg
Weight of the block, W = m × g 
W= 10 × 9.8 
W= 98 N
Dimension of block from the side of pressure 20 cm × 40 cm
Area = 20 cm × 40 cm
Area = 800 cm2 
Area= 800 × 10-4 m2
Thrust on the table is due to the weight of the wooden block.
Thrust on the table = weight of the block 
Thrust on the table= 98 N
The thrust also known as force acting on one unit area is called pressure. The relation between them is given below.
Pressure=ThrustArea Pressure=ForceArea
On putting all the values in above relation. Pressure will be.
P= FA
P=98 800 × 10-4
P= 1220 N/m2
 
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