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Q.

A wooden block of mass 8 kg slides down an inclined plane of inclination 30∘to the horizontal with a constant acceleration of 0.4 m/s2.. What is the force of friction between the box and inclined plane? ( Take g = 10 m/s2)

 

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a

36.8 N

b

65.6 N

c

76.8 N

d

None of these

answer is A.

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Detailed Solution

mgsinθ-f=ma f=force of friction or f=mgsinθ-a               =810×12-0.4               =36.8 N             

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