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Q.

A wooden block of mass M resting on a rough horizontal floor is pulled with a force F at an angle $ϕ$ with the horizontal. If $μ$ is the coefficient of kinetic friction between the block and the surface, then the acceleration of the block is:

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a

$\frac{F}{M} (\cos ϕ - μ \sin ϕ) - μg$

b

$\frac{μF}{M} \cos ϕ$

c

$\frac{F}{M} (\cos ϕ + μ \sin ϕ) - μg$

d

$\frac{F}{M} \sin ϕ$

answer is C.

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Detailed Solution

$N = Mg - F \sin ϕ$

Question Image

From figure

$a = \frac{F \cos ϕ - μ (Mg - F \sin ϕ)}{M}$

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A wooden block of mass M resting on a rough horizontal floor is pulled with a force F at an angle ϕ with the horizontal. If μ is the coefficient of kinetic friction between the block and the surface, then the acceleration of the block is: