A wooden cube floating in water supports a mass $m = 0.2 k g$ on its top. When the mass is removed the cube rises by $2 c m .$ The side of the cube is (density of water $= 10^{3} k g / m^{3}$ )

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6 cm

12 cm

8 cm

10 cm

answer is D.

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Detailed Solution

Decrease in weight = Decrease in Upthrust

Or $mg = V ρ_{w} g$ Or $m = V ρ_{w}$

Or $(0.2) = (2 \times 10^{- 2}) (A) (10^{3})$

Or $A = 10^{- 2} m^{2} = 100 {cm}^{2}$

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