A wooden object the same in water in a beaker. The object is near a side of the beaker as shown in figure. Let P₁, P₂, P₃ be the pressure at the three points A, B and C of the bottom as shown in the  figure

If a liquid's pressure changes at one place, the change propagates across the liquid without losing any of its magnitude.

Pressure is constant within a liquid at any given depth. Block floating has no impact on this effect.

${\mathrm{P}}_1={\mathrm{P}}_2={\mathrm{P}}_3$

Hence the correct answer is ${\mathrm{P}}_1={\mathrm{P}}_2={\mathrm{P}}_3.$