Q.

A wooden wheel of radius R is made of two semicircular parts (as in figure) the two parts are held together by a ring made of a metal strip of cross sectional area s and length L. L is slightly less than 2πR . To fit the ring on the wheel, it is heated so that its temperature rises by T and it just steps over the wheel. As it cools down to surrounding temperature, it presses the semicircular parts together. If the co-efficient of linear expansion of the metal is α and its Young's modulus y then, the force that one part of the wheel applies on the other part is 

Question Image

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

2πSYαT

b

SYαT

c

πSYαT

d

2SYαT

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given,

length =L and cross-sectional area =S
Temperature change = △T 
Y is Young's Modulus
Now, the force that one wheel component exerts on the other component is,

Y=stressstrain=FlAl______(1)

strain=ll=αT

substituting the values,

Y=FTF=SYαT

Hence the correct answer is SYαT.

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon