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A Young’s double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and interference pattern is observed on the screen at a distance 1.33 m from plane of slits. The wavelength of light in air is $6300 \overset{0}{A}$ . Find the distance (in mm) of middle of seventh bright fringe from middle of third bright fringe lying on the same side of central bright fringe.

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answer is 2.52.

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Detailed Solution

$β' = \frac{D λ}{μ d} = \frac{1.33 \times 6300 \times 10^{- 10}}{1.33 \times 1 \times 10^{- 3}} = 0.63 m m 7 β' - 3 β' = 4 B' = 2.52 m m$

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