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Q.

A Young’s double slit interference arrangement with slits  S1 in air and  S2 is immersed in water (refractive index = 3/2) as shown in the figure.  The positions of  maxima on the surface of water are given by  x2=p2m2λ2d2,  where λ  is the wavelength of light in air (refractive index = 1), 2d is the separation between the slits and m is an integer.  The value of  p is

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answer is 2.

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Detailed Solution

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μ(S2P)S1P=mλ μd2+x2d2+x2=mλ (μ1)d2+x2=mλ 321d2+x2=mλ
Or
Squaring this equation we get,
x2=4m2λ2d2

P2=4 or P=2

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