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Q.

A Young’s double slit interference arrangement with slits S1 and S2 is immersed in a liquid (refractive index = 1.4) as shown in the figure. The positions of the maxima on the surface of liquid are given by 𝑥2 = (25/𝑝)m2λ2d2, where 𝜆 is the wavelength of light in air (refractive index = 1), 2𝑑 is the separation between the slits and 𝑚 is an integer. The value of 𝑝 is ______.
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answer is 4.

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Detailed Solution

Path difference at distance x is given by
Δx=1.4x2+d2=x2+d2=>0.4x2+d2==>254m2λ2d2 =P=4

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