Q.

A young’s double slit interference arrangement with slits  S1 and S2  is immersed in water (refractive index=4/3) as shown in the figure. The positions of maxima on the surface of water are given by x2=p2m2λ2d2, where λ is the wavelength of light in air (refractive index=1), 2d is the separation between the slits and m is an integer. The value of p is 

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answer is 3.

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Detailed Solution

S1P=x1=d2+x2             S2P=x2=μd2+x2         Δx=x2x1            Δx=13x2+d2

For maxima  Δx=mλ

x2+d2=9m2λ2x2=9m2λ2d2         P=3

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