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A young's double-slit arrangement produces interference fringes for sodium light $(λ = 5890 Å)$ that are $0 . 20^{0}$ apart. What is the angular fringe separation (in degree) if the entire arrangement is immersed in water? (refractive index of water is 4/3).

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Detailed Solution

$\begin{array}{l} If β be the fringe width in air, then in water \\ β_{water} = \frac{β}{μ_{w}} = \frac{{0.20}^{\circ}}{4 / 3} = {0.15}^{0} \end{array}$

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