Q.

A young’s double slit interference arrangement with slits  S1 and S2 is immersed in water (refractive index= 4/3) as shown in the figure. The positions of maxima on the surface of water are given by  x2=p2m2λ2d2, where  λ is the wavelength of light in air (refractive index=1), 2d is the separation between the slits and m is an integer. The value of  p is

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Detailed Solution

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x2=P2m2λ2d2 Optical path differences, Δx=S1PS2P=x2+d2μx2+d2mλ=x2+d2(1μ)m2λ2=x2+d21+μ22μ=x2+d21+16983=x2+d2189m2λ2=19x2+d29m2λ2=x2+d2P=3

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A young’s double slit interference arrangement with slits  S1 and S2 is immersed in water (refractive index= 4/3) as shown in the figure. The positions of maxima on the surface of water are given by  x2=p2m2λ2−d2, where  λ is the wavelength of light in air (refractive index=1), 2d is the separation between the slits and m is an integer. The value of  p is