A zener diode in the circuit shown has a knee current of 5 mA and a maximum allowed power dissipation of 300 mW. What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage V₀ constant at 6 volts ?

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0 mA, 180 mA

5 mA, 110 mA

10 mA, 55 mA

60 mA, 180 mA

answer is C.

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Detailed Solution

Current from source is

$I = (9 - 6) / 50 = . 06 A$

= 60 mA

$Now, I_{z min} = 5 mA and$

$I_{z max} = P_{max} / V_{z} = 300 mW / 6 V = 50 mA$

So,

$L_{max} = I - I_{z min} = 60 mA - 5 mA = 55 mA$

And

$L_{min} = I - I_{z max} = 60 mA - 50 mA = 10 mA$

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