A $10 H$ inductor carries a current of $20 A$. How much of a substance could be melted by the energy stored in the magnetic field of the inductor? Latent heat of the substance is $2.26\times {10}^{3}J/kg$

Energy stored is $\frac{1}{2}L{i}^2$.

This energy is completely used in melting the ice.

Hence, $\frac{1}{2}L{i}^2=m{L}_f$

Here, $L_f$= latent heat of fusion

Hence, mass of ice melted, $m=\frac{L{i}^2}{2L_f}$

Substituting the values, we have

$$\begin{gathered} m=\frac{\left(10\right){\left(20\right)}^2}{2(2.26\times {10}^3)} \\ =0.88 kg \end{gathered}$$