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A $1.50$ gm sample of type metal (an alloy of Sn, Pb, Cu and Sb is dissolved in nitric acid and metastannic acid, $H_{2} {SnO}_{3}$ , precipitates. This is dehydrated by heating to Tin(IV)oxide, which is found to weigh . What percentage of tin was in the original type metal sample? (Sn = $119$ )

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33.33 %

26.27 %

29.38 %

52.54 %

answer is B.

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Detailed Solution

$\frac{\frac{0.5}{151} \times 119}{1.5} \times 100$

$= 26.27 %$

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