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A $200 k g$ car is rolling at $10 m / s$ when its fuel tank explodes into four pieces. If $40 k g$ of it goes forward at $75 m / s$ , $80 k g$ goes backwards, $30 k g$ goes to the left at $10 m / s$ , and a piece goes to the right.

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Speed of the mass that went to the right is $6 m / s$

Speed with which the $80 k g$ piece is moving backwards is $25 m / s$

Speed of the mass that went to the right is $12 m / s$

Speed with which the $80 k g$ piece is moving backwards is $12.5 m / s$

answer is A, D.

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Detailed Solution

$200 \times 10 (\hat{i}) = 40 \times 75 \hat{i} + 80 \times v_{2} (- \hat{i}) + 30 \times 10 (+ \hat{j}) + 50 \times v_{4} (- \hat{j}) v_{2} = 12.5 m / s, v_{4} = 6 m / s$

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