$A 20$ litre container at $400 K$ contains ${CO}_{2} (g)$ at pressure $0.4 a t m$ and an excess of $SrO$ (neglect the volume of solid $SrO$ ). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of ${CO}_{2}$ attains its maximum value, will be
[Given that $t : {SrCO}_{3} (s) ⇌ SrO (s) + {CO}_{2} (g), Kp = 1.6 atm$ ]

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$2 l i t r e$

$10 l i t r e$

$5 l i t r e$

$4 l i t r e$

answer is D.

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Detailed Solution

$\begin{matrix} {SrCO}_{3} (s) ⇌ SrO (s) + {CO}_{2} (g) \\ K_{p} = P_{{CO}_{2}} \end{matrix}$

maximum pressure of ${CO}_{2} = 1.6 atm$

$\begin{aligned} P_{1} V_{1} = P_{2} V_{2} \\ 0.4 \times 20 = 1.6 V_{2} \Rightarrow V_{2} = 5 L \end{aligned}$

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