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Q.

A $2.5 k g$ block is initially at rest on a horizontal surface. A $6.0 N$ horizontal force and a vertical force are applied to the block as shown in figure. The coefficient of static friction for the block and surface is $0.4$ . The magnitude of friction force when $P = 9 N$ : $(g = 10 m / s^{2})$

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a

zero

b

$6.0 N$

c

$9.0 N$

d

$6.4 N$

answer is A.

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Detailed Solution

$f_{l i m} = μ N = 0.4 (25 - 9) = 6.4 N$

External force is $6 N$ so block will not move. So frictional force $= 6.0 N$

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A 2.5 kg block is initially at rest on a horizontal surface. A 6.0 N horizontal force and a vertical force are applied to the block as shown in figure. The coefficient of static friction for the block and surface is 0.4. The magnitude of friction force when P=9N : (g=10 m/s2)