$\overrightarrow{A}=2\hat{i}+\hat{j}+\hat{k} \& \overrightarrow{B}=\hat{i}+\hat{j}+\hat{k}$are two vectors, then the unit vector

parallel to $\overrightarrow{A}$ is $\frac{2\hat{i}+\hat{j}+\hat{k}}{\sqrt{6}}$

perpendicular to $\overrightarrow{A}$ is $\frac{\hat{I}+\hat{j}+\hat{k}}{\sqrt{3}}$

perpendicular to $\overrightarrow{B}$ is $\frac{-\hat{j}+\hat{k}}{\sqrt{2}}$

perpendicular to $\overrightarrow{A}$ is $\frac{-\hat{j}+\hat{k}}{\sqrt{2}}$