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A $4.00 k g$ block carrying a charge $Q = 50.0 μ C$ is connected to a spring for which $k = 100$ The block lies on a frictionless horizontal track, and the system is immersed in a an electric field of magnitude $E = 5.00 \times 10^{5} V / m$ , directed as shown in figure. The block released from rest when the spring is unstretched (at $x = 0$ ) .
If the coefficient of kinetic friction between block and surface is $0.2$ , find the maximum elongation produced in the spring.

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$1.34 m$

$0.34 m$

$3.34 m$

$4.34 m$

answer is A.

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Detailed Solution

$μ m g = 0.2 \times 4 \times 10 = 8 N$

Therefore, here net constant force $F$ = $q E - μ m g = 25 - 8 = 17 N = F$ (say)

By work energy theorem , F $x_{m a x} = \frac{1}{2} k {x^{2}}_{m a x}$

$X_{\max} = \frac{2 F}{K} = \frac{2 \times 17}{100} = 0.34 m$

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