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A $4^{o} C$ rise in temperature is observed in a conductor by passing a certain current .When the current is doubled ,the rise in temperature will be

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$16 ° C$

$12 ° C$

$9 ° C$

$3 ° C$

answer is A.

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Detailed Solution

$i_{1}^{2} Rt = {msΔθ}_{1} i_{2} = 2 i_{1} {msΔθ}_{2} = i_{2}^{2} Rt {msΔθ}_{2} = 4 i_{1}^{2} Rt = 4 {msΔθ}_{1} {msΔθ}_{2} = 4 ms . 4 {Δθ}_{2} = 16 ° C$

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