A=500102436100,B=13042012 and AB=C=(c)ij then the elements of second row of C is

A=500102436100,B=13042012 C=AB⇒the second row of C is 0+0+8+3, 0+8+0+6 i.e 11,14

A=500102436100,B=13042012 and AB=C=(c)ij then the elements of second row of C is

A=500102436100,B=13042012 C=AB⇒the second row of C is 0+0+8+3, 0+8+0+6 i.e 11,14

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$A = [\begin{matrix} 5 & 0 & 0 & 1 \\ 0 & 2 & 4 & 3 \\ 6 & 1 & 0 & 0 \end{matrix}], B = [\begin{matrix} 1 & 3 \\ 0 & 4 \\ 2 & 0 \\ 1 & 2 \end{matrix}]$ and $A B = C = {(c)}_{i j}$ then the elements of second row of C is

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14, 11

17, 6

22, 6

11, 14

answer is D.

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Detailed Solution

$A = [\begin{matrix} 5 & 0 & 0 & 1 \\ 0 & 2 & 4 & 3 \\ 6 & 1 & 0 & 0 \end{matrix}], B = [\begin{matrix} 1 & 3 \\ 0 & 4 \\ 2 & 0 \\ 1 & 2 \end{matrix}] C = A B \Rightarrow t h e s e c o n d r o w o f C i s 0 + 0 + 8 + 3, 0 + 8 + 0 + 6 i . e 11, 14$

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