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A $72 -$ $k g$ boy and a $42 - k g$ girl, both wearing skates face each other at rest on a skating rink. The boy pushes the girl, sending her eastward with a speed of $9 m / s .$ Neglecting friction, determine the subsequent speed of the boy.

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$3.25 m / s$

$4.25 m / s$

$5.25 m / s$

$15.4 m / s$

answer is A.

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Detailed Solution

$m_{1} v_{1} - m_{2} v_{2} = 0$

$\Rightarrow v_{1} = \frac{m_{2} v_{2}}{m_{1}} = \frac{42 \times 9}{72} = 5.25 m / s$

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