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Q.

aa+ba+2ba+2baa+ba+ba+2ba=

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a

9b2(a+b)

b

9a2(a+b)

c

9(a+b)3

d

9ab(a+b)

answer is A.

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Detailed Solution

=aa+ba+2ba+2baa+ba+ba+2ba

R1R1R2+R3 =3(a+b) 111a+2baa+ba+ba+2ba =3(a+b) 100a+2b-2b-ba+bb-b                            C2C2-C1                         C3C3-C1 =33b2(a+b) 100a+2b-2-1a+b1-1 =3b2 (a+b) (3) =9b2 (a+b)      

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