A)Area bounded by $\sqrt{\mathrm{x}} +\sqrt{\mathrm{y}} = 2$ and coordinate axes
B) Area bounded by y² = 4x and x² = 4y
C)Area bounded by y = 4x + x² between x = 0, x = 1, X-axis
D)Area bounded by y² = 4x and y = 2x
Arrange the above statements in the ascending order of areas.

A)Area bounded by $\sqrt{\mathrm{x}} +\sqrt{\mathrm{y}} = 2$ and coordinate axes is $\frac{16}{6}=\frac{8}{3}$

B) Area bounded by y² = 4x and x² = 4y is$\frac{16ab}{3}=\frac{16}{3}$

C)Area bounded by y = 4x + x² between x = 0, x = 1, X-axis=${\int }_0^1\left(4x+x^2\right)dx={\left(2x^2+\frac{x^3}{3}\right)}_0^1=2+\frac{1}{3}=\frac{7}{3}$

D)Area bounded by y² = 4x and y = 2x is

${\int }_0^1\left(2\sqrt{x}-2x\right)dx={\left(\frac{4}{3}{x}^{\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}-x^2\right)}_0^1=\frac{4}{3}-1=\frac{1}{3}$

A=8/3,B=16/3,C=7/3,D=1/3