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Q.

$A B, A_{2}, B_{2}$ are diatomic molecules with bond enthalpies 1 : 1 :0.5 and enthalpy of formation of AB from $A_{2}, B_{2}$ is -100KJ/ mole. Incorrect statement about bond enthalpy of $A_{2}$ .

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a

400KJ/mole

b

200KJ/mole

c

300KJ/mole

d

100KJ/mole

answer is B, C, D.

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Detailed Solution

$\frac{1}{2} A_{2} + \frac{1}{2} B_{2} \to A B Δ H = - 100 K J$

$- 100 = (\frac{X}{2} + \frac{X}{4}) - X$

$- 100 = \frac{- X}{4} \Rightarrow X = 400$

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