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Q.

AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to $387 P m$ . The distance between two oppositely charged ions in the lattice is

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a

$250 P m$

b

$200 P m$

c

$335 P m$

d

$300 P m$

answer is A.

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Detailed Solution

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For b.c.c lattice body diagonal $= a \sqrt{3}$

The distance between the two oppositely charged ions $= \frac{a}{2} \sqrt{3}$

$= \frac{387 \times 1.732}{2} = 335 P m$

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