AB is an ionic solid. If the ratio of ionic radii of A⁺ and B^- is 0.52. What is the co-ordination number of B^-?

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answer is C.

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Detailed Solution

Coordination Number Based on Radius Ratio

If the ratio of ionic radii of A⁺ and B^- (i.e., r₊/r_-) is 0.52, the coordination number is determined by the radius ratio rules for ionic solids.

If the radius ratio r₊/r_- is between 0.414 and 0.732, the coordination number is 6.
0.52 falls in this range.

Therefore, the coordination number of B^- in the ionic solid AB is 6.
Additionally, the corresponding geometry is octahedral.

For clarity: the coordination number refers to the number of nearest neighbors. In this context, since 0.52 is between 0.414 and 0.732, the coordination number is 6, and this is the number of A⁺ ions around each B^- ion (or vice versa, depending on the crystal structure). The question asks about B^-, but in a simple AB ionic solid, the coordination number is the same for both ions in a regular arrangement.

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