Q.

AB2 is 10% dissociated in water to A2+ and B- ,the boiling point of a 10.0 molal aqueous solution of AB2 is C  . (Round off to the Nearest Integer).
[Given: Molal elevation constant of water Kb=0.5Kkgmol-1 boiling point of pure water =100°C

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 106.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

t=0,   AB2  A2++2 B- t=t,  a-aα      aα      2aα

nT=a-aα+aα+2aα       =a(1+2α)

 so i=1+2α
Now  ΔTb=i×m×Kb
ΔTb=(1+2α)×m×Kb
α=0.1   m=10   Kb=0.5
ΔTb=1.2×10×0.5=6
So, the boiling point =106.

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon