$A + B ⟶ A_{3} B_{2}$ (unbalanced)
$A_{3} B_{2} + C ⟶ A_{3} B_{2} C_{2}$ (unbalanced)
Above two reactions are carried out by taking 3 moles each of 3 and A and one mole of B. Then which option is/are correct?

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$1 mole of A_{3} B_{2}$ is formed from first reaction

$1 mole of A_{3} B_{2} C_{2}$ is formed

$\frac{1}{2} mole of A_{3} B_{2} C_{2}$ is formed

$\frac{1}{2} mole of A_{3} B_{2}$ is left finally

answer is B, C, D.

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Detailed Solution

$3 A + 2 B \to A_{3} B_{2} \begin{array}{ccc} 3 & 3 & - \\ - & 1 & 1 \end{array}$

$A_{3} B_{2} + 2 C \to A_{3} B_{2} C_{2} \begin{array}{lll} 1 1 \\ \frac{1}{2} - \frac{1}{2} \end{array}$

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