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$A^{+} + B ⇌ B^{+} + A; E_{cell}^{o} = + 0 .295 V .$ Equilibrium constant for the reaction is

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$10^{10}$

$10^{5}$

$10^{20}$

$10^{15}$

answer is B.

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Detailed Solution

n = 1

$E_{cell}^{o} = \frac{0 .0591}{n} \log K$

$0 .295 = \frac{0 .0591}{1} \log K$

$K = 10^{5}$

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