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Q.

ABC is a triangle whose medians AD and BE are perpendicular to each other. If AD = p and BE = q then area of $Δ A B C$ is

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a

$\frac{2}{3} p q$

b

$\frac{3}{4} p q$

c

$\frac{4}{3} p q$

d

$\frac{3}{2} p q$

answer is D.

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Detailed Solution

$A G = \frac{2}{3} A D = \frac{2}{3} p$ , $B G = \frac{2}{3} B E = \frac{2}{3} q$

Question Image

Area of $Δ A B C =$ 3 area of $Δ A B G$

$= 3 (\frac{1}{2} A G \times B G)$

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ABC is a triangle whose medians AD and BE are perpendicular to each other. If AD = p and BE = q then area of ΔABC is