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Q.

ABC is an equilateral triangle. Three identical charges each +q are placed at each corner. Electric intensity at the centriod of triangle is

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a

$\frac{1}{4 π \in_{0}} \frac{q}{r^{2}}$

b

$\frac{1}{4 π \in_{0}} \frac{q}{r}$

c

Zero

d

$\frac{1}{4 π \in_{0}} \frac{3 q}{r^{2}}$

answer is C.

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Detailed Solution

The net upward field is equal to net down ward field

Question Image

u p w a r d E_{n e t} = 2 E \cos \frac{θ}{2} = 2 E \cos \frac{120}{2} = E d o w n w a r d E_{n e t} = E

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