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Q.

ABCD is a rectangle in which AB=10cms, BC=8cms. A point p is taken on AB such that PA=x . Then the minimum value of PC2+PD2 is obtained when x=

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a

8

b

10

c

4

d

5

answer is D.

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Detailed Solution

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If PA=x,PC2+PD2=(10x)2+64+x2+64=2x210x+114

P(x)=0x=5

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