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ABCD is a square frame made of metallic wire. The corners A and C are joined together by another metallic wire. The currents in different branches are as shown in the figure.
A uniform magnetic field of induction B = 1.5 T exists in that region whose direction is perpendicular to the plane of the frame ABCD. Then the net magnetic force experienced by the frame is [Length of side of the square ABCD is 1m]

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18.48 N

16 N

12.32 N

14.85 N

answer is D.

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Detailed Solution

Equivalent length of branch ABC and ADC

$\begin{array}{l} l_{e f f} = \sqrt{1^{2} + 1^{2}} m = \sqrt{2} m \\ F = i l B \\ ∴ F_{net} = (2 \times \sqrt{2} \times 1 .5 + 3 \times \sqrt{2} \times 1 .5 + 2 \times \sqrt{2} \times 1 .5) N \\ = 14 .85 N \end{array}$

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