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ABCDEF is a regular hexagon in anticlockwise sense and A (2,0), B (4,0) then the coordinates of C are

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$(\frac{9}{2}, \sqrt{3})$

$(5, \sqrt{3})$

$(\frac{5}{2}, \frac{\sqrt{3}}{2})$

$(2, \frac{\sqrt{3}}{2})$

answer is B.

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Detailed Solution

Let C be (x,y)

$\begin{array}{l} \Rightarrow \frac{x - 4}{\cos 60^{0}} = \frac{y - 0}{\sin 60^{0}} = 2 \\ ∴ x = 5; y = \sqrt{3} \end{array}$

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