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Q.

A+BC+D Initially the concentration of A and B are both equal but at equilibrium concentration of D will be twice of that of A then what will be equilibrium constant of reaction is

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a

19

b

49

c

29

d

4

answer is D.

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Detailed Solution

A+B=C+D

 Initial conc     1    1    0    0

 Eq. conc 1x 1x x x

 i.e., x=2×1

KC=x×x(1x)(1x)=2×2(21)(21)=4

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