$\mathrm{A}+\mathrm{B}\to {\mathrm{CH}}_3-\mathrm{OC}{\left({\mathrm{CH}}_3\right)}_3\stackrel{\mathrm{HI}}{⟶}\mathrm{X}+\mathrm{Y}.$
Correct statement among the following is

Reaction of t-Butyl Methyl Ether with HI

Starting Material: t-butyl methyl ether (CH₃-O-C(CH₃)₃)

Reagent: HI (hydroiodic acid)

The correct statement regarding this reaction is:

When t-butyl methyl ether reacts with HI, it forms methanol (CH₃OH) and t-butyl iodide ((CH₃)₃CI) as products.

Products Formed:

• Product X: Methanol (CH₃OH) - from the methyl group
• Product Y: t-butyl iodide ((CH₃)₃CI) - from the t-butyl group

Reaction Mechanism:

• HI cleaves the ether at the O–CH₃ bond due to steric hindrance
• The reaction proceeds via S_N1 pathway
• Formation of stable t-butyl carbocation intermediate
• Methyl group forms methanol while t-butyl group forms t-butyl iodide