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ABC is any triangle and P is a point on the side BC. If Q is a point such that $PQ = AP + PB + PC$ , then

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$AQ = AB + BC + AC$

Q is fixed for all position of P on BC

Q depends on the position of P

$AQ = AB + AC - BC$

answer is B.

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Detailed Solution

$OQ - OP = OP - OA + OB - OP + OC - OP OQ = OB + OC - OA$

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