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$A B is a chord of the parabola y^{2} = 4 a x with vertex A \cdot B C is drawn perpendicular to A B meeting the axis at C . The$
$projection of B C on the axis of the parabola is$

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$a$

$4 a$

$2 a$

$8 a$

answer is C.

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Detailed Solution

$\begin{array}{l} \tan θ = \frac{y}{x} \\ The projection of B C on the x -axis, \end{array}$

$L C = \frac{y}{\tan (90^{\circ} - θ)} = y \tan θ = \frac{y^{2}}{x} = 4 a$

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