Q.

AC voltage V(t) = 20 sinωt of frequency 50Hz is applied to a parallel plate capacitor. The separation between the plates is 2mm and area is 1m2. The amplitude of oscillating displacement current for applied AC voltage is___________ μA.(Take0=8.85×1012  F/m)

(Round off to nearest integer)
 

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answer is 28.

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Detailed Solution

Displacement current  i=Cdvdt i=C20wcoswt  
Amplitude of displacement current is Imax = C20w  =(0Ad)20(2πf)  =(8.85×1012×12×103)20(2π×50)27.79μA=28μA 

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