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Q.

Acceleration-displacement graph of a particle executing S.H.M is as shown in the given figure. The time period of its oscillation is (in sec)

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a

π /4

b

2 π

c

π

d

π /2

answer is B.

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Detailed Solution

The slope of the graph gives

ω^{2}

$then \tan θ = \tan 45 ° = 1$

$a = ω^{2} x \Rightarrow \frac{a}{x} = ω^{2} \Rightarrow ω = 1$

$\frac{2 π}{T} = 1$

$T = 2 π \sec$

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