Acceleration of a particle moving in a straight line varies with the velocity v (in ms) as a=2(2-v) ms2 . Find the maximum possible speed of the particle assuming at t=0 particle was at rest

A =2(2-v)= 4-2v dvdt=4−2vFor Max possible speed dvdt=04=2v V=2ms

Acceleration of a particle moving in a straight line varies with the velocity v (in ms) as a=2(2-v) ms2 . Find the maximum possible speed of the particle assuming at t=0 particle was at rest

A =2(2-v)= 4-2v dvdt=4−2vFor Max possible speed dvdt=04=2v V=2ms

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Acceleration of a particle moving in a straight line varies with the velocity v $(i n \frac{m}{s})$ as a=2(2-v) $\frac{m}{s^{2}}$ . Find the maximum possible speed of the particle assuming at t=0 particle was at rest

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$2 \frac{m}{s}$

$1 \frac{m}{s}$

$4 \frac{m}{s}$

$3 \frac{m}{s}$

answer is A.

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Detailed Solution

A =2(2-v)= 4-2v
$\frac{d v}{d t} = 4 - 2 v$
For Max possible speed $\frac{d v}{d t} = 0$
4=2v
$V = 2 \frac{m}{s}$

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Acceleration of a particle moving in a straight line varies with the velocity v (in ms) as a=2(2-v) ms2 . Find the maximum possible speed of the particle assuming at t=0 particle was at rest

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Acceleration of a particle moving in a straight line varies with the velocity v $(i n \frac{m}{s})$ as a=2(2-v) $\frac{m}{s^{2}}$ . Find the maximum possible speed of the particle assuming at t=0 particle was at rest