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Q.

Acceleration of electron in the first orbit of the hydrogen atom is $\frac{h^{2}}{2^{p} π^{2} m^{2} r^{3}}$ . Find p.

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answer is 2.

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Detailed Solution

According to Bohr’s postulate
$\begin{array}{l} mvr = \frac{nh}{2 π} \\ m^{2} v^{2} r^{2} = \frac{n^{2} h^{2}}{4 π^{2}} \\ v^{2} = \frac{n^{2} h^{2}}{4 π^{2} m^{2} r^{2}} \\ \frac{v^{2}}{r} = a_{c} = \frac{n^{2} h^{2}}{4 π^{2} m^{2} r^{3}} \end{array}$

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