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Q.

Acceleration versus time graph of a particle starting from rest and moving along a straight line is as shown. The displacement after 20 s is

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a

632 m

b

592 m

c

608 m

d

518 m

answer is B.

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Detailed Solution

For 0<t<10, it is having constant acceleration of 4ms-2 and zero initial velocity. 

for 10<t<18, it is moving with a constant velocity of 40ms-1.

for 18<t<20, it is moving with a acceleration of -4ms-2 and initial velocity of 40ms-1.

S=12×4×102+(4×10)×8+40×2+12(4)22

=(200+4008)m=592m

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